College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 11 - Problems - Page 427: 1

Answer

The intensity of the sunlight that reaches Jupiter is $52~W/m^2$

Work Step by Step

We can find an expression for the intensity at the Earth: $I_E = \frac{P}{A}$ $I_E = \frac{P}{\pi~R_E^2}$ We can find the intensity at Jupiter: $I_J = \frac{P}{A}$ $I_J = \frac{P}{\pi~R_J^2}$ $I_J = \frac{P}{\pi~(5.2~R_E)^2}$ $I_J = \frac{1}{(5.2)^2}\times \frac{P}{\pi~R_E^2}$ $I_J = \frac{1}{(5.2)^2}\times I_E$ $I_J = \frac{1}{(5.2)^2}\times (1400~W/m^2)$ $I_J = 52~W/m^2$ The intensity of the sunlight that reaches Jupiter is $52~W/m^2$.
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