College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 10 - Problems - Page 401: 68

Answer

The new period of this pendulum is $2.8~s$

Work Step by Step

We can write an expression for the original period of the pendulum: $T = 2\pi~\sqrt{\frac{L}{g}}$ The period does not depend on the mass of the bob, so changing the mass of the bob does not affect the period. We can write an expression for the new period of the pendulum: $T' = 2\pi~\sqrt{\frac{2L}{g}}$ $T' = \sqrt{2}\times 2\pi~\sqrt{\frac{L}{g}}$ $T' = \sqrt{2}\times T$ $T' = (\sqrt{2})(2.0~s)$ $T' = 2.8~s$ The new period of this pendulum is $2.8~s$.
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