College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 10 - Problems - Page 398: 14

Answer

Since the diameter is twice the radius, the diameter of the hair is $8.7\times 10^{-5}~m$

Work Step by Step

We can find the radius: $\frac{F}{A} = 2.0\times 10^8~N/m^2$ $A = \frac{F}{2.0\times 10^8~N/m^2}$ $\pi~r^2 = \frac{F}{2.0\times 10^8~N/m^2}$ $r = \sqrt{\frac{F}{(\pi)(2.0\times 10^8~N/m^2)}}$ $r = \sqrt{\frac{1.2~N}{(\pi)(2.0\times 10^8~N/m^2)}}$ $r = 4.37\times 10^{-5}~m$ Since the diameter is twice the radius, the diameter of the hair is $8.7\times 10^{-5}~m$
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