Answer
The abductin ligament is compressed by $0.48~mm$
Work Step by Step
$Y = \frac{F/A}{\Delta L/L}$
$Y$ is Young's modulus
$F$ is the force
$A$ is the cross-sectional area
$\Delta L$ is the change in length
$L$ is the original length
We can find the change in length:
$\Delta L = \frac{F~L}{Y~A}$
$\Delta L = \frac{(1.5~N)(1.0\times 10^{-3}~m)}{(4.0\times 10^6~N/m^2)(0.78\times 10^{-6}~m^2)}$
$\Delta L = 4.8\times 10^{-4}~m = 0.48~mm$
The abductin ligament is compressed by $0.48~mm$.
