Answer
The correct answer is:
(c) $0~s, 1~s, 7~s, 8~s$
Work Step by Step
When the slope of the $v_x$ versus $t$ graph is positive, the acceleration is positive. That is, the acceleration is in the +x-direction. If the acceleration is in the +x-direction, then the net force is in the +x-direction.
The slope of the graph is positive in the intervals $0 \leq t \lt 2$ and $6 \lt t \lt 10$
Therefore, the net force is in the +x-direction in the intervals $0 \leq t \lt 2$ and $6 \lt t \lt 10$
The correct answer is:
(c) $0~s, 1~s, 7~s, 8~s$
