College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Section 1.5 - Units - Practice Problem - Page 10: 1.7

Answer

The surface area of the Earth is $~5.1\times 10^{14}~m^2~$ The surface area of the Earth is $2.0 \times 10^8~mi^2$

Work Step by Step

We can find the surface area of the Earth: $A = 4\pi~r^2$ $A = (4\pi)~(6.4\times 10^6~m)^2$ $A = 5.1\times 10^{14}~m^2$ We can convert the surface area to units of square miles: $A = 5.147\times 10^{14}~m^2 \times (\frac{1~mi}{1609~m})^2 = 2.0 \times 10^8~mi^2$ The surface area of the Earth is $~5.1\times 10^{14}~m^2~$ The surface area of the Earth is $2.0 \times 10^8~mi^2$
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