Answer
Please see the work below.
Work Step by Step
We know that
$a=gsin(\theta)$
$a=9.8sin(35)=5.621\frac{m}{s^2}$
Now we can find the distance as
$d=\frac{v^2}{2a}$
$d=\frac{(2.2)^2}{(2)(5.621)}=0.43m$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 5 - Exercises and Problems - Page 91: 39
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