Answer
Please see the work below.
Work Step by Step
We know that
$a=\frac{F}{M}$
$a=\frac{F_{\circ}sin(\omega t)}{M}=\frac{F_{\circ}}{M}sin(\omega t)$
We also know that the jerk is the rate of change of acceleration
$J=\frac{da}{dt}$
$J=\frac{-F\omega{\circ}}{M}cos(\omega t)$
The maximum jerk is given as
$J_{max}=\frac{F_{\circ}\omega}{M}$
