Answer
$(1.3i+2.3j)\space m/s$
Work Step by Step
Please see the image first.
Let's apply equation $V=u+at$ to the object to find its velocity to $y$ direction after 4.4 seconds.
$\uparrow V=u+at$
Let's plug known values into this equation.
$V=0+0.52\space m/s^{2}\times 4.4\space s$
$V=2.3\space m/s$
We know, the acceleration occurred in the $y$ direction. Hence $x$ direction velocity component remains the same after 4.4 s.
We know the velocity vector can be expressed as,
$$\vec{V} =V_{x}i+V_{y}j$$
$$\vec{V}=(1.3i+2.3j)\space m/s$$
