Answer
11
Work Step by Step
We adjust equation 18.11b to obtain:
$\frac{V_z{max}}{V_{min}} = (\frac{T_{max}}{T_{min}})^{1/(\gamma-1)}$
$\frac{V_{max}}{V_{min}} = (\frac{773}{293})^{1/(1.4-1)}\approx 11$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 18 - Section 18.2 - Thermodynamic Processes - Example - Page 335: 18.3
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