Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Section 18.2 - Thermodynamic Processes - Example - Page 332: 18.2

Answer

.94 Joules

Work Step by Step

We simplify the ideal gas law as well as the equation $p_1V_1=p_2V_2$ to find: $W = nRTln(\frac{V_2}{V_1})=\frac{4}{3}\pi r^3p\ ln(3.5)$ $W ==\frac{4}{3}\pi (.008)^3(350)\ ln(3.5)=9.4\times10^{-4}kJ=.94\ J$
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