Answer
1150 K
Work Step by Step
We know that the temperature is given by:
$ \frac{P}{4 \pi e R^2 \sigma}$
We plug in the known values to find:
$ T = (\frac{34,000}{.341425* 5.7* 10^{4}})^{1/4}*10^3$
$T=1150 K$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 16 - Exercises and Problems - Page 311: 69
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