Answer
$ -10^{\circ}C$
$263.15 K$
Work Step by Step
We use the following equation to find: $\frac{h}{h_3} = \frac{T}{T_3}$ $\frac{57.8}{60} = \frac{T}{273.16}$ $ T = -10^{\circ}C$
This is the same as 263.15 degrees Kelvin.
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 16 - Exercises and Problems - Page 310: 45
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