Answer
Please see the work below.
Work Step by Step
We know that
$P=\rho gh$
This can be rearranged as:
$\rho=\frac{P}{gh}$
We plug in the known values to obtain:
$\rho=\frac{100000}{9.8(6.0)}$
$\rho=1700\frac{Kg}{m^3}$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 15 - Exercises and Problems - Page 289: 17
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