Answer
110 Newtons
Work Step by Step
We find:
$F = \mu v^2 = (\frac{m}{L})(\frac{L}{t})^2 = \frac{mL}{t^2} = \frac{(5)(43)}{1.4^2} \approx 110 \ N$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 14 - Section 14.3 - Waves on a String - Example - Page 255: 14.2
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