Answer
$ v = \frac{\omega A}{\sqrt{2}}$
Work Step by Step
We find:
$ \frac{1}{2}mv^2 = \frac{1}{2}(\frac{1}{2}m\omega^2A^2)$
$ \frac{1}{2}mv^2 =(\frac{1}{4}m\omega^2A^2)$
$ v = \frac{\omega A}{\sqrt{2}}$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 13 - Section 13.5 - Energy in Simple Harmonic - Example - Page 240: 13.5
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