Answer
(a)$\tau=(\frac{L}{2})mg$
(b)0
(c)$\tau=(\frac{L}{2})mg$
Work Step by Step
We know that
(a) $\tau=r\times F$
$\implies \tau=(\frac{L}{2})mg$
(b) $\tau=r\times F$
$\implies \tau=(0)mg$
$\tau=0$
(c) $\tau=r\times F$
$\tau=-(\frac{L}{2})mg$