Answer
a) 1.61
b) The day increases by a factor of 2.221.
Work Step by Step
a) We find:
$\frac{R}{R_0}=(\sqrt[3] {\frac{1}{1-.8^3}})^2 = 1.61$
b) Using the equation for the volume of a sphere and the equation for moment of inertia, we find that $r^2\times r^3 =r^5$. Consequently, we can find the ratios of periods to be:
$=(1.27)^5\times(1-.8^5)=2.221$
The day increases by a factor of 2.221.
