Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 11 - Exercises and Problems - Page 207: 29

Answer

(a) $0.29\space kgm^{2}/s$ (b) Downward

Work Step by Step

(a) Here we use the equation, Angular momentum (L) = mrV ; where, m - mass of the ball, r - radius of circle, V - speed of the ball $L=mrV$ ; Let's plug known values into this equation. $L=58.2\times10^{-3}kg\times84.3\times10^{-2}m\times5.87\space m/s$ $L=28800\times10^{-5}kgm^{2}/s$ $L=0.29\space kgm^{2}/s$ (b) To find the direction, we use the right-hand rule. Then we can find the direction as downward.
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