Answer
$I = MR^2$
Work Step by Step
We take the integral to find:
$I = \int R^2dm$
R is constant for a ring, so we can take it out of the integral.
$I = R^2\int dm$
$I = MR^2$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 10 - Section 10.3 - Rotational Inertia and the Analog of Newton’s Law - Example - Page 182: 10.6
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