Answer
$a)$ CCl$_{4}$
$b)$ AlH$_{3}$
$c)$ CH$_{2}$Cl$_{2}$
$d)$ SIF$_{2}$
$e)$ CH$_{3}$NH$_{2}$
Work Step by Step
$a)$ C would be the central atoms, and since it has 4 valence electrons to share, it would most likely do so completely with 4 Cl atoms
$b)$ Al would be the central atom here, sharing 3 of its valence electrons with 3 H atoms
$c)$ C would have 4 electrons to share, two are already taken by the two Cl atoms, so two would still be left, which would be shared to 2 H atoms.
$d)$ Si has 6 valence electrons. In order to complete its octet it would need two more, which it could get from sharing electrons with two F
$e)$ N has 5 valence electrons. In order to complete its octet it would need to three more, which it could get from sharing electrons. Since it is already sharing one from bonding with C (C-N), there need only two more atoms of H.
