General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 3 - Matter and Energy - 3.5 Energy and Nutrition - Questions and Problems - Page 79: 3.30

Answer

A) 830 kJ B) 5 grams C) 160 Kcal D) 950 Kcal

Work Step by Step

To answer item A, we need to multiply the amount of carbohydrate (6 grams) by the value of 17Kj/g, and the amount of protein (7 grams) by the value of 17Kj/g and the amount of fat (16 grams) by 38kJ/g (see table 3.7 for values;, after that we need to sum the results and finally round off the final value to have the answer. (6 × 17) + (16 × 38) + (7 × 17) = 829 KJ (final result 830KJ ) To answer item B, we must multiply the values ​​in grams (9 grams of carbohydrates and 6 grams of fat) by the respective values ​​in the table 3.7 and sum its results; after that, decrease the previous result from the value of Kcal given by the question and then divide the result (20Kcal) by the value of 4kcal / g. $\frac{[110Kcal−(9g×4Kcal/g + 6g×9Kcal/g)]}{4}$ = 5 grams To answer item C, we need to multiply the amount of carbohydrates (40 grams) by the value of 4Kcal/g (see table 3.7 for values); after that we need round off the result to have the answer. 40g $\times$ 4Kcal/g = 160 Kcal To answer item D, we need to multiply the amount of carbohydrate (68 grams) by the value of 4 Kcal/g, and the amount of protein (150 grams) by the value of 4Kcal/g and the amount of fat (9 grams) by the value of 9 Kcal/g (see table 3.7 for values); after that we need to sum the results round off the final value to have the answer. (68g $\times$ 4Kcal/g) + (9g $\times$ 9Kcal/g) +( 150g $\times$ 4Kcal/g) =953 Kcal (final answer 950Kcal)
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