General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 3 - Matter and Energy - 3.3 Temperature - Questions and Problems - Page 73: 3.20

Answer

A) (°C x $\frac{9}{5}$) + 32 = 145°F °C=$\frac{5(145-32)}{9}$ °C= 62.7778 B) (°C x $\frac{9}{5}$) + 32 = °F °F =(20.6°C x $\frac{9}{5}$) + 32 °F=37.08+32 °F=69.08

Work Step by Step

To answer this question you need to know the formula for converting from degrees Celsius to degrees Fahrenheit: (°C x 9/5 )+ 32 = °F A) (°C x $\frac{9}{5}$) + 32 = 145°F °C=$\frac{5(145-32)}{9}$ °C= 62.7778 B) (°C x $\frac{9}{5}$) + 32 = °F °F =(20.6°C x $\frac{9}{5}$) + 32 °F=37.08+32 °F=69.08 (for a more detailed explanation look on Chapter 3 - Matter and Energy - 3.3 Temperature - pages 69 to 72).
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