Answer
$4 ms^{-1}$
Work Step by Step
$\Delta v\geq \dfrac{h}{4\pi\cdot m\Delta x}\geq \dfrac{6.63\cdot 10^{-34}m^2kgs^{-1}}{4\cdot 3.14\cdot 6.65\cdot 10^{-27}kg\cdot (\pm 2 \times 10^{-9}m)}\geq \pm 4 ms^{-1} $
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