Answer
(Isotopic Mass of B-10)(Abundance of B-10) + (Isotopic Mass of B-11) (Abundance of B-11) = Atomic Mass of Boron
Suppose x = Abundance of B-10
This implies that Abundance of B-11 = 1-x
Therefore
(10.013)(x) + (11.009)(1-x) = 10.811
10.013x + 11.009 – 11.009x = 10.811
-0.996x = -0.198
x = 0.1987
1 – x = 1 – 0.1987
= 0.8012
Abundance of B-10 = 19.9%
Abundance of B-11 = 80.1%
Work Step by Step
As given in answer
