Answer
P$_{4}$O$_{10}$ = (4 x 30.973762) + (10 x 15.9994)
= 123.895 + 159.994 = 283.889
Mass %age of phosphorus = 123.895/283.889 x 100 = 43.64206%
Phosphorus in Fertilizer = 43.642 x 18/100 = 7.8556 g
Work Step by Step
Given in answer