Answer
0.821 M
Work Step by Step
We find:
$\text{Moles of solute}=69.0\,g\times\frac{1\,mol\,NaHCO_{3}}{84.007\,g}=0.82136\,mol$
$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Liters of solution}}=\frac{0.82136\,mol}{1.00\,L}=0.821\,M$
General Chemistry (4th Edition)
by McQuarrie, Donald A.
Published by
University Science Books
ISBN 10:
1891389602
ISBN 13:
978-1-89138-960-3
Chapter 12 Chemical Calculations for Solutions - Problems - Page 414: 1
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