Answer
(a) CaSO$_{4}$ is insoluble by Rule 6.
H$_{2}$SO$_{4}$ (aq) + Ca(ClO$_{4}$)$_{2}$ (aq) → CaSO$_{4}$ (s) + 2 HClO$_{4}$ (aq) SO$^{2-}_{4}$ (aq) + Ca$_{2}$+(aq) → CaSO$_{4}$ (s)
(b) All compounds are soluble; thus there is no reaction.
(c) Hg$_{2}$ (C$_{7}$H$_{5}$O$_{2}$)$_{2}$ is insoluble by Rule 3.
Hg$_{2}$ (NO$_{2}$)$_{2}$ (aq) + 2 NaC$_{7}$H$_{5}$O$_{2}$ (aq) → Hg$_{2}$ C$_{7}$H$_{5}$O$_{2}$)$_{2}$ (s) + 2 NaNO$_{3}$ (aq) Hg$_{2}$+(aq) + 2 C$_{7}$H$_{2}$O$_{2}$ –(aq) → Hg$_{2}$ (C$_{7}$H$_{5}$O$_{2}$)$_{2}$ (s)
(d) PbBr$_{2}$ is insoluble by Rule 3.
Pb(CH$_{3}$COO)$_{2}$ (aq) + 2 KBr(aq) → PbBr$_{2}$ (s) + 2 KCH$_{3}$COO(aq) Pb$_{2}$+(aq) + 2 Br–(aq) → PbBr$_{2}$ (s)
Work Step by Step
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