Answer
(a) iridium(III) bromide tetrahydrate
IrBr$_{3}$. 8H$_{2}$O
(b) tin(IV) chloride pentahydrate
SnCl$_{4}$. 5H$_{2}$O
(c) zinc nitrate hexahydrate Zn(NO$_{3}$)$_{2}$. 6 H$_{2}$O
(d) sodium carbonate monohydrate
NaCO$_{2}$ . H$_{2}$O
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