General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 6 - Gases - Exercises - General Gas Equation - Page 232: 23

Answer

4.30 L

Work Step by Step

We find: $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$ $\implies V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}$ $=\frac{(748\, mmHg)(4.25\,L)(26.8+273)\,K}{(25.6+273)\,K\times (742\, mmHg)}$ $=4.30\,L$
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