General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Density - Page 29: 59

Answer

0.0182 mm

Work Step by Step

Volume=$\frac{\text{mass}}{\text{density}}=\frac{2.568\,g}{2.70\,g/cm^{3}}=0.95111\,cm^{3}$ Volume=area of the square$\times$thickness $\implies 0.95111\,cm^{3}=(22.86\,cm)^{2}\times\text{thickness}$ Or thickness of the foil=$\frac{0.95111\,cm^{3}}{(22.86\,cm)^{2}}=0.00182\,cm$ $=0.0182\,mm$ (As 1 cm=10 mm)
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