General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Density - Page 28: 49

Answer

$$d = 0.792 \space g/mL$$

Work Step by Step

$$m_{acetone} = 437.5 \space lb - 75.0 \space lb = 362.5 \space lb$$ $$m_{acetone} = 362.5 \space lb \times \frac{1 \space kg }{2.20 \space lb} \times \frac{1000 \space g}{1 \space kg} \approx 164800 \space g$$ $$V = 55.0 \space gal \times \frac{1 \space L}{0.264 \space gal} \times \frac{1000 \space mL}{1 \space L} \approx 208000 \space mL$$ $$d = \frac{m}{V} = \frac{164800 \space g}{208000 \space mL} = 0.792 \space g/mL$$
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