General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Example 1-5 - Applying Significant Figure Rules: Multiplication/Division - Page 22: Practice Example A

Answer

$21.3$ or $2.13\times10^{1}$

Work Step by Step

The least precisely known quantity, $0.000456$, has three significant figures. As this is a case of division or multiplication, the final result must also contain only three significant figures. We perform the calculation $\frac{62.356}{0.000456\times6.422\times10^{3}}$ by using an electronic calculator. The result displayed on the calculator is 21.29331 Rounding off to three significant figures, the result is properly expressed as $21.3$ or $2.13\times10^{1}$
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