Answer
a) 3.8g
b) 1.03mL
c) 564cm^3
Work Step by Step
a) $18.02g\div4.8g$=3.7542g, which is rounded to 2 sig figs because the least amount of sig figs in the initial calculation is 2.
b) $7.87mL\div7.66mL$= 1.0274mL, which is rounded to 3 sig figs because the least amount of sig figs in the initial calculation is 3.
c) (pi is assumed to be 3.14) $V=3.14\times6.23cm^{2}\times4.630cm$ is the calculation with all of the variables plugged in. V=564.230, which is rounded to 3 sig figs because the least amount of sig figs in the initial calculation is 3.
