Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 4 - Reactions in Aqueous Solution - Exercises - Page 159: 4.48b

Answer

Work Step by Step

H2SO3. Hydrogen is +1 (except in metal hydrides, which this is not) and we have 2 of them so that is +2. Oxygen is -2 so we have 3*-2 = -6. Since H2SO3 is neutral, it means that the sum of the oxydation numbers is 0 Therefore, we have: 0 = 2 - 6 + Oxidation number Sulfur Oxidation Number Sulfur = 6 - 2 = +4

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