Answer
$Al_2S_3 + 6 H_2O ->2Al(OH)_3 + 3H_2S$
Work Step by Step
1. Write the unbalanced equation:
$Al_2S_3 + H_2O -> Al(OH)_3 + H_2S$
2. Now, balance the number of Aluminum atoms :
$Al_2S_3 + H_2O ->2Al(OH)_3 + H_2S$
3. Balance the number of Sulfur atoms:
$Al_2S_3 + H_2O ->2Al(OH)_3 + 3H_2S$
4. Balance the number of Hydrogen atoms:
$Al_2S_3 + 6H_2O ->2Al(OH)_3 + 3H_2S$
5. We dont need to change anything to balance the number of Oxygen atoms:
$Al_2S_3 + 6H_2O ->2Al(OH)_3 + 3H_2S$
