Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 113: 3.11c

Answer

CH4 + 4Cl2 -> CCl4 + 4HCl

Work Step by Step

CH4 + Cl2 -> CCl4 + HCl First we balance the C since it appears only once and it seems simple. There is 1 C on the left and 1 on the right so it is done. Next we balance the Hs since it appears only once on each side. There are 4 on the left and 1 on the right so we need to multiply the HCl term by 4 CH4 + Cl2 -> CCl4 + 4HCl Now we balance the Cls. We have 2 on the left and 8 on the right so we multiply the Cl2 by 4 to give 8 CH4 + 4Cl2 -> CCl4 + 4HCl

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