Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 112: 3.5c

Answer

3 moles of Glycine $\times\frac{75 grams}{ 1-mole-of- Glycine}$ = 225 grams of Glycine

Work Step by Step

For every one mole of glycine, we know that there are 75 grams of glycine. Knowing this, one can use dimensional analysis to find the amount of grams in 3 moles of glycine. One will multiply 3 moles by 75 grams over 1 mole. Moles will cancel out and the final unit will be in grams of glycine.
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