Answer
C10H12N2O
Work Step by Step
68.2 % C, 6.86% H, 15.9% N and 9.08 % O
Taking a basis of 100g we now have
68.2 g C, 6.86g H, 15.9g N, 9.08g O.
Converting to moles we have
C is 12 g/mol so 68.2g is 5.68 moles
H is 1g/mol so 6.86g is 6.86 moles
N is 14g/mol so 15.9g is 1.14 moles
O is 16g/mol so 9.08g is 0.568 moles
Now we divide each of these by the smallest number, 0.568
5.68/0.568 = 10
6.86/0.568 = 12
1.14/0.568 = 2
0.568/0.568 = 1
The ratio is 10:12:2:1 or
C10H12N2O
This would have a molar mass of
10*12 = 120
12*1 = 12
14*2 = 28
16
176 g/mol.
Therefore, the empirical formula is the molecular formula
