Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 2 - Atoms, Molecules, and Ions - Exercises - Page 77: 2.74e

Answer

$Co(HCO_3)_2$

Work Step by Step

This is an ionic compound, so the cation is what is listed first (Cobalt). The Roman numerals tell us that the cation has a charge of 2+. The anion is what is listed second (Hydrogen Carbonate). This anion has a formula of $HCO_3$, and a charge of -1. To have a neutral compound, there needs to be twice as many Hydrogen Carbonate molecules as Cobalt, hence $Co(HCO_3)_2$.

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