Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning
ISBN 10: 0534420125
ISBN 13: 978-0-53442-012-3

Chapter 7 - Electronic Structure - Questions and Exercises - Exercises - Page 288: 7.93

Answer

$\Delta x = 1.8\times10^{-37}m$ This value is negligible.

Work Step by Step

$\Delta x\Delta p$ = $\frac{h}{4π}$ Or $\Delta x.m\Delta v$ = $\frac{h}{4π}$ $\Delta x = \frac{h}{4π.m.\Delta v}$ h = $6.626\times10^{-34}Js$ m = 650 kg $\Delta v$ = 1 mile/hr = 1609.34 m/3600s $\Delta x = \frac{6.626\times10^{-34}Js}{4π\times650 kg\times\frac{1609.34m}{3600s}}$ = $1.8\times10^{-37}m$
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