Chapter 7 - Electronic Structure - Questions and Exercises - Exercises - Page 285: 7.30

a) $3.05\times10^{-7}\,m$ b) $6.51\times10^{-19}\,J$ c) $392\,kJ/mol$

a) $\lambda=\frac{c}{\nu}=\frac{3.00\times10^{8}\,m/s}{9.83\times10^{14}Hz}=3.05\times10^{-7}\,m$ b) $E= h\nu=6.626\times10^{-34}\,m^{2}\,kg/s\times9.83\times10^{14}Hz=$ $6.51\times10^{-19}\,J$ c) E for 1 mol= $6.51\times10^{-19}\,J\times\frac{6.022\times10^{23}}{1\,mol}=3.92\times10^{5}\,J=392\,kJ$