Chapter 3 - Equations, the Mole, and Chemical Formulas - Questions and Exercises - Exercises - Page 133: 3.49

$6NO + 4NH_{3} → 5N_{2} + 6H_{2}O$ Oxidation states (reactants): N = +2 and -3, O = -2, H = +1 Oxidation states (products): N = 0, O = -2, H = +1 N is both oxidized and reduced, while all other remain unchanged.

$6NO + 4NH_{3} → 5N_{2} + 6H_{2}O$ Oxidation states (reactants): N = +2 and -3, O = -2, H = +1 Oxidation states (products): N = 0, O = -2, H = +1 N is both oxidized and reduced, while all other remain unchanged.