Answer
17.0 days.
Work Step by Step
$\ln (\frac{N}{N_{0}})=-\frac{0.693}{t_{1/2}}t$
$\implies t_{1/2}=-\frac{0.693}{\ln (\frac{N}{N_{0}})}t=-\frac{0.693}{\ln(\frac{650}{865})}\times7.00\,days=17.0\,days$
Chemistry: Principles and Practice (3rd Edition)
by Reger, Daniel L.; Goode, Scott R.; Ball, David W.
Published by
Cengage Learning
ISBN 10:
0534420125
ISBN 13:
978-0-53442-012-3
Chapter 21 - Nuclear Chemistry - Questions and Exercises - Exercises - Page 934: 21.39
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