Answer
62.5 mm Hg
Work Step by Step
$P_{1}$ = 100. mm Hg
$V_{1}$ = 125 mL
$V_{2}$ = 200. L
According to Boyle's law, $P_{1}V_{1} = P_{2}V_{2}$
⇒ $P_{2}$ = $\frac{P_{1}V_{1}}{V_{2}}$ = $\frac{100. mm Hg\times125 mL}{200. mL}$ = 62.5 mm Hg
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 8 - Properties of Gases - Questions for Review and Thought - Topical Questions - Page 370a: 18
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