Answer
M = 132, Xenon
Work Step by Step
20.0-g sample of a pure gas in a 2.50-L sealed flask at 10.0 °C is
1.41 atm
P = 1.41 atm, m = 20.0 g, V = 2.5 L, T = 273.15 + 10 = 283.15 K
M = mRT/PV
M = 20 x 0.0821 x 283.15 / 1.41 x 2.5 = 132 g/mol
Xenon has the molar mass mass of 131.3 g/mol, wich is very close to 132 g/mol.