Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 8 - Properties of Gases - Problem Solving Practice 8.3 - Page 336: b

Answer

21 mL

Work Step by Step

$P_{1}=P_{2}=740.\, mmHg$ $T_{1}=(22.3+273)K=295.3\,K$ $T_{2}= (26.5+273)K=299.5\,K$ $V_{1}=21\,mL$ As the amount of gas and pressure are constant, we can use Charles's law to find the final volume $V_{2}$. $\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$ $\implies V_{2}=\frac{V_{1}T_{2}}{T_{1}}=\frac{21\,mL\times299.5\, K}{295.3\,K}=21\,mL$
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