Answer
4s electrons in $Cr^{2+}$ are at a higher energy level than 3d electrons. Hence, it loses its 4s electrons to attain the configuration of $[Ar]3d^{4}$.
Work Step by Step
As above
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 5 - Electron Configurations and the Periodic Table - Questions for Review and Thought - Topical Questions - Page 240b,: 54
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