Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 5 - Electron Configurations and the Periodic Table - Questions for Review and Thought - Topical Questions - Page 240: 15

Answer

$E=4.4*10^{-19}$

Work Step by Step

We know that: $E = \frac{hc}{ \lambda}$ When we substitute, we find: $E = \frac{6.625*10^{-34}*3*10^8}{ 450*10^{-9}}$ $E=4.4*10^{-19}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.