Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 5 - Electron Configurations and the Periodic Table - Problem Solving Practice 5.1 - Page 193: a

Answer

(a) $3.00 \times 10^{-7}m$ (b) 300. nm

Work Step by Step

Frequency $\times$ Wavelength = Velocity Speed of light: $2.998 \times 10^{8} m/s$ $9.99 \times 10^{14} \times λ = 2.998 \times 10^{8}$ $λ = \frac{2.998 \times 10^{8}}{9.99 \times 10^-7} = 3.00 \times 10^{-7}$ (a) $3.00 \times 10^{-7}m$ 1 nanometer = $10^{-9}m$ $3.00 \times 10^{-7}m \times \frac{1 nm}{10^{-9}m} = 300. nm$ (b) 300. nm.
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